A satellite of mass 250 kg is orbiting the earth at a height of 500 km above the surface of the earth. How much energy must be expended to rocket the satellite out of the gravitational influence of the earth? Mass of earth = `6 xx 10^24`kg Radius of earth = 6400km.

A satellite of mass m is revolving around the earth at a height x above the surface of the earth. The radius of the earth is R. If the acceleration due to gravity is g, the orbital speed of the satellite will be

As you have learnt in the text ,a geostationary satellite orbits the earth at a height of nearly 36000 km from the surface of the earth. What is the potential due to earth's gravity at the site of this satellite? (Take the potential energy at infinity to be zero.) Mass of the earth= 6.0xx10^(24)kg , radius =6400 km.

At what height above the surface of the earth will the acceleration due to gravity be half of its value on the earth's surface ? Radius of the earth =6400 km.

An artificial satellite revolves around the earth in a circular orbit and is at a height of 300 km above the surface of the earth. Find the orbital speed and the time period of the satellite. The radius of the earth=6400 km, g=980 cm*s^(-2) .

An artificial satellite is revolving around the earth at an altitude h above the surface of the earth. Show that the orbital speed and the time period of revolution of the satellite is independent of its mass.

An artificial satellite is moving in an orbit around the earth with a velocity equal to one-third the escape velocity from the surface of the earth. (i) Find the height of the satellite from the surface of the earth.