Discuss the variation of g (ii) with depth below the earth's surface.

Discuss the variation of g (i) with the height above the earth's surface

Discuss the variation of g with depth. What happens to g at the centre of earth?

If the change in the acceleration due to gravity (g) at an altitude h above the earth's surface is equal to the change in g at a depth x below the earth's surface [assume that both x and h are significantly smaller than the radius of the earth], then

The value of the acceleration due to gravity at a height h from the surface of the earth is g_1 and that at a depth h below the earth's surface is g_2 .Show that (g_2)/(g_1)=(1+h/R) [Radius of earth Rgt gt h ]

The value of the acceleration due to gravity at a height h from the surface of the earth is g_1 and that at a depth h below the earth’s surface is g_2 . Show that g_2/g_1 = (1+h/R) (Radius of earth R >> h) I.

Imagine earth to be a solid sphere of mass M and radius R. If the value of acceleration due to gravity at a depth d below earth's surface is same as its value at a height h above its surface and equal to (g)/(4) (where g is the value of acceleration due to gravity on the surface of earth), the ratio of (h)/(d) will be

Calculate the value of ‘g' at height ‘h' from the earth’s surface.

Calculate the height from earth’s surface at which value of g is 1% than that of the earth surface.