The mass and diameter of a planet are twice those of the earth.What will be the period of oscillation of a pendulum on this planet,If it's a 2 second's pendulum on the earth?

The time period of a seconds pendulum is

The length of a seconds pendulum on the surface of the earth is

If both the radius and the mean density of a planet are half the radius and the mean density of the earth, what will be the acceleration due to gravity on the surface of that planet ? Given that the acceleration due to gravity on the earth's surface =980 cm*s^(-2)

The mass and radius of a satellite is twice that of the earth. If a seconds pendulum is taken to that satellite, what will be its time period?

The mass of a planet is 4 times the mass of the earth and its radius is 2 times the radius of the earth. The acceleration due to gravity on that planet is

What is the work done by the tension in the string during the oscillation of a simple pendulum ?

Consider a simple pendulum having a bob attached to a string that oscillates under the action of the force of gravity. Suppose that the period of oscillation of the simple pendulum depends on its length (l) , mass of the bob (m) and acceleration due to gravity (g). Derive the expression for its time period using the method of dimensions.