A body hanging from a spring stretches it by 1 cm at the earth's surface.How much will the same body stretch the spring at a place 1600 km above the earth's surface? Radius of earth =6400km.

At what height above the surface of the earth will the acceleration due to gravity be half of its value on the earth's surface ? Radius of the earth =6400 km.

A rocket is launched vertically from the surface of the earth with an initial velocity of 10km/s .How far above the earth would it go?Radius of earth =6400kkm.

Find the percentage decrease in the weight of a body when taken 32 km below the surface of the earth. Take radius of earth =6400 km.

An artificial satellite is moving in an orbit around the earth with a velocity equal to one-third the escape velocity from the surface of the earth. (ii) The satellite comes to rest in its orbit and then is allowed to fall freely on to the surface of the earth. Find the speed with which the satellite strikes the earth's surface. Given radius of earth =6400 km.

When a body coming from infinity falls on the earth's surface, give its velocity .

Find the percentage decreases in weight of a body, when taken 16 km below the surface of the earth. Take radius of the earth as 6400 km.

At what height above the surface of earth acceleration due to gravity will be (ii) 50% of its value on the surface of the earth. Given radius of earth =6400 km.

The weight of a body is different at different heights from the earth's surface-why?

The height vertically above the earth's surface at which the acceleration due to gravity becomes 1% of its value at the surface is (R is the radius of the earth)

A body weight 90 kgf on the surface of earth. How much will it weight on the surface of a planet whose mass is 1/9 and radius 1/2 that of the earth ?