A wire `(Y =2xx10^11N//m^2)` has length 1m and area `1mm^2`. Calculate the work required to increase its length by 2mm.

The area of cross section of a steel wire (Y=2.0xx10^11 N//m^2) is 0.1 cm^2 . The force required to double its length will be

The cross-sectional area of a steel rod of length 25 cm is 0.8 cm^(2) . What tension will be required to incresase the length of the rod, equal to the increase due to its rise in temeprature by 10^(@)C ? For steel, Y=2 times 10^(12)dyn*cm^(-2) " and " alpha=10^(-5@)C^(-1) .

A body of mass 4 kg and density 2.5 g.cm^-3 , suspended by a metallic wire of length 1 m and diameter 2mm, is kept completely immersed in water. What will be the increase in the length of the wire? Young's modulus of the metal =2 times 10^11 N.m^-2 and g=9.8 m.s^-2 .

How much load should be hung from the end of a steel wire of length 3.14 m and of diameter 1 mm so that it increases in length by 1mm? Y for steel is 2 times 10^11 SI unit.

A metal sphere has a diameter of 1m. What will be the amount of charge required to rate its potential by 2.7 xx 10^(6)V ?

Cross sectional area of a steel wire is 1 cm^2 .How much force is required to increase its length to twice its initial length? Young's modulus for steel is 2 times 10^12 dyn.cm^-2 .

For a uniform wire of length 3 m and cross sectional area 1mm^2 , 0.021 J of work is necessary to stretch it through 1mm. Calculate the Young's modulus for its material.

A cube has a side of length 1.2 xx 10^-2 m calulate the volume________.