When a 4kg mass is hung vertically on a light spring that obeys Hooke's law, the spring stretched by 2cm. Calculate the work required to be done by an external agent in stretching this spring by 5cm.

When a spring is stretched by 10 cm, the potential energy stored is E. When the spring is stretched by 10 cm more, the potential energy stored in the spring becomes

When a spring is stretched by 3 cm, stored potential energy becomes u and when it is stretched by 6 cm potential energy becomes

A spring of spring constant 5xx10^3 N//m is stretched initially by 5cm from the unstretched position. Calculate the work required to stretch it further by another 5cm.

Work done for a certain spring when stretched through 1mm is 10J . The amount of work that must be done on the spring to stretch if further by 1mm is

When a spring is stretched by an amount 3 cm , the potential energy stored in the spring is U. if the spring is stretched by an amount 6 cm its stored potential energy is

A long spring is stretched by 2 cm. its potential energy is U . If the spring is stretched by 10 cm , its potential energy would be

An elastic spring of length L and of force constant k is stretched to increase its length by an amount x. The spring is further stretched to elongate it by y. The amount of work done in stretching the spring in the second case ( x and y are very small) is