The poisson’s, ratio of a material is `sigma`. If a longitudinal strain of a wire made in thin material be `prop`, show that its volume strain is `(1-2sigma)prop`.

Define Poisson's ratio. The poisson's ratio of a material is sigma . If a longitudinal strain of a wire made of thin material be a, show that its volume strain is (1-2sigma)a

The poison’s ratio of a material is 0.4. If a force is applied to a wire of this material, there is a decrease of cross-sectional area by 0.2 %. The percentage increase in its length is

A material has Poisson 's ratio 0.50 . If a uniform rod it suffers a longitudinal strain of 2 xx 10 ^(-3) then the percentage change in volume is

A force of 10^6 N.m^-2 is required for breaking a material. IF the density of the material is 3 times 10^3 kg.m^-3 , then what should be the length of the wire made of this material , so that it breaks due its own weight? [ g=9.8 m.s^-2 ]

The Young's modulus of a metal is 2 xx 10^(12) "dync/cm"^(2) - and its breaking stress is 11000 kg//"cm"^2 . In case of longitudinal strain the maximum energy that can be stored per cubic metre of this metal is approximately (Assume g = 10 m//s^2 )

The lengths diameters and resistances of two wire are in the ratio of 1:2 Determine the ratio of the resistivities for their materials.

The change in length of a wire of a circular cross section is found to be 0.01% due to longitudinal stress, IF the poisson's ratio for the material is 0.2, what is the percentage change in volume?

The lengths,resistances and resistivities of materials of two wires-each is in the ratio of 1:2 What is the ratio between their diameters?