The density of a body is d and that of air is `rho`. If the body weighs W in air, show that the actual weight of the body is `=W/(1-rho/d)`

The density of a body is d and that of air is rho . If the body weighs w in air, what will be its actual weight?

The density of a body is d and that of air is rho . Prove that the real weight of the body, weighed W in air, is W_(0)=W/(1-rho//d) .

The weights of a body in air and water are W and W' respectively. Prove that the apparent weight of the body when immersed in a liquid of density delta will be W''=W-(W-W')delta .

A body in water weighs three-fourths of its weight in air. Calculate the density of the body in S.I. unit.

The air pressure on our body is equal to

The weight of a body in air is 100 g and its weight in water is 40 g. Find the volume of the body.

Determine the change in potential energy of a body when it is raised through a height h, inside water. Volume of the body is V, its density is rho and the density of water is rho_(0) . Given your answer for the situations when (i) rhogtrho_(0) and (ii) rholtrho_(0) .

The weight of a body on the surface of the earth is W. The weight of that body at an altitude equal to half the radius of the earth will be