At `30^@C`, the hole in a steel plate has diameter of 0.99970 cm. A cylinder of diameter exactly 1cm at `30^@C` is to be slide into the hole. To what temperature the plate must be heated?
(Given : `alpha_(steel)=1.1xx10^-5//^@C`)

A metallic cylinder of diameter 5cm. And height 3(1)/(3) cm is melted and cast into a sphere. What is its diameter.

A square metal plate of side 100 cm at 0^(@)C , has a circular hole of diameter 40 cm in the middle of it. At what temperature, will each side by 101 cm long? What will be the diameter of the hole at that temperature? alpha for the metal =12.5 times 10^(-6@)C^(-1)

A hole is drilled in a copper sheet. The diameter of the hole is 4.24 cm at 27^@C . What is the change in the diameter of the hole when the sheet is heated to 227^@C ? Coefficient of linear expansion of Cu=1.7xx10^-5 "^@c-1

A copper collar is to fit tightly about a steel shaft that has a diameter of 6 cm at 20^(@)C . The inside diameter of the copper collar at that temperature is 5.98 cm. To what temperature must the copper collar be raised so that it will just slip on the steel shaft, assuming the steel shaft remains at 20^(@)C ? (alpha_("cooper")=17 times 10^(-6)K^(-1))

An iron sphere is to be passed through a circular brass ring. At 20^(@)C , the diameter of the sphere is 25 cm and the internal diameter of the ring is 24.9 cm. If both the sphere and the ring are heated together, at what temperature will the sphere just pass through the ring? alpha for iron =1.2 times 10^(-5@)C^(-1) and alpha for brass =2times10^(-5@)C^(-1) .

In a cistern there is water up to a depth of 1.2 m. There is a circular hole of diameter 1 cm at the bottom of the cistern. To stop the flow of water through this hole, what force should be applied on the hole?

A steel ring is heated up to 95^(@)C to fit exacty on the outer surface of an iron cylinder of diameter 10 cm at 20^(@)C. After fitting, the ring is cooled so that the system attains a temperature 20^(@)C. What is the thermal stress of the ring? [Young's modulus of steel = 21 times 10^(5)kg*cm^(-2) " and " alpha for steel =12 times 10^(-6@)C^(-1).]