The distance of the particle in simple harmonic motion is 2 cm from equilibrium then its kinetic energy is doubled to its potential energy, for what distance its potential energy is double to its kinetic energy?

A particle executives simple harmonic motion of amplitude A. The distance from the mean position where its kinetic energy is equal to its potential energy is

When a particle executing SHM is at a distance of 0.02 m from its position of equilibrium, then its kinetic energy is twice its potential energy. Calculate the distance from the position of equilibrium where its potential energy is twice its kinetic energy.

If the frequency of a simple harmonic motion be n then find the frequency of its kinetic energy.

How will the momentum of a body change if its kinetic energy is doubled ?

Can a body have negative value of potential energy and kinetic energy ?

At which points of its path, for a particle executing simple harmonic motion, will its velocity, acceleration, kinetic energy and potential energy be zero?

How will the kinetic energy of the body change if its momentum in doubled ?

For a particle executing simple harmonic motion, find the distance from the mean position at which its potential and kinetic energies are equal.