The time period and amplitude of a particle executing SHM are 10s and 12 cm respectively. Find its velocity of a distance 4 cm for its position of equilibrium.

The time period and amplitude of a particle executing SHM are 10 s and 0.12 m respectively. Find its velocity at a distance 0.04 m from its position of equilibrium.

Time period and amplitude of a particle executing SHM are 2 s and 5 cm respectively. Determine its velocity and acceleration at a distacne of 3 cm from the equilibrium position.

An object of mass 10 kg executes SHM. Its time period and amplitude are 2s and 10 m respectively. Find its kinetic energy when it is at a distance of (i) 2 m and (ii) 5 m respectively from its position of equilibrium. Justify the two different results for (i) and (ii).

A particle of mass 0.01 kg is executing simple harmonic motion along a straight line. Its time period is 2 s and amplitude is 0.1 m. Determine its kinetic energy (i) at a distance 0.02 m and (ii) at a distance 0.05 m from the position of equilibrium.

A particle of mass 0.5g is executing SHM with a time period of 2s and an amplitude of 5 cm. Calculate its (i) maximum velocity, (ii) maximum acceleration and (iii) velocity, acceleration and force acting on the particle when it is at a distance of 4 cm from its position of equilibrium.

The time period of a particle executing S.H.M. is T sec. Find the time taken by the particle to reach maximum displacement in one side from equilibrium position.

If the mass of a particle executing SHM is m and its angular frequency is omega , then time period of its oscillation will be