A particle executing SHM completes 1200 cycle in a minute and when it crosses the equilibrium position its velocity is 3.14 m/s .
Find the equation of motion of that particle [assume the displacement is zero at t = 0]

When a particle executing SHM is at a distance of 0.03 m from the equilibrium position, its acceleration is 0.296m*s^(-2) . What is the time period of oscillation of the particle?

Write the equation of motion of a particle executing simple harmonic motion, whose displacement is maximum at t = 0.

Write the equation of motion of a particle executing SHM if at t = 0 its displacement is maximum.

The maximum acceleration of a particle executing simple harmonic motion is 0.296m*s^(-2) , its time period is 2s and the displacement from the equilibrium position at the beginning of its motion is 0.015m. Determine the equation of motion of the particle.

The velocity of a particle executing a simple harmonic motion is 13m*s^(-1) , when its distance from the equilibrium position (Q) is 3 m and its velocity is 12m*s^(-1) , when it is 5 m away from Q. The frequency of the simple harmonic motion is

A particle executes SHM with an amplitude of 13 cm and its velocity at a distance of 5 cm from the equilibrium position is 36cm*s^(-1) . Determine the maximum value of the restoring force. (Mass of the particle = 2g).

A particle of mass 5g is executing SHM. The velocity of the particle when it crosses the midpoint of its motion is 10cm*s^(-1) . What will be its total mechanical energy?

The ratio of kinetic energy and potential energy of a particle executing SHM at a distance of 2 cm from its equilibrium position is 3 : 2. What is the amplitude of vibration of the particle?

For what displacement from the equilibrium position of a particle executing SHM, its velocity will be one fourth of its maximum velocity?