Total energy of a particle executing simple harmonic motion is 3 joule. The greatest force that acts on the particle is 1.5 newton. The time period of the S.H.M. is 2 s and epoch is `30^@`. Find the equation of motion.

Total energy of a particle executing simple harmonic motion is 400 erg and the maximum force acting on the particle is 100 dyn. If the time period is 2 s and the initial phase is 30^(@) , then write down the equation of motion. What is the mass of the particle?

The maximum acceleration of a particle executing simple harmonic motion is 0.296m*s^(-2) , its time period is 2s and the displacement from the equilibrium position at the beginning of its motion is 0.015m. Determine the equation of motion of the particle.

For a particle executing simple harmonic motion, find the distance from the mean position at which its potential and kinetic energies are equal.

Find expressions for potential and kinetic energies of a particle executing simple harmonic motion.

Total energy of a particle executing SHM is 3 J. A maximum force of 1.5 N acts on it. Time period and epoch of the SHM are 2s and 30^(0) respectively. Establish the equation of this SHM and also find the mass of the particle.

Write the equation of motion of a particle executing simple harmonic motion, whose displacement is maximum at t = 0.