Mass and diameter of a satellite is double that of the earth. Find the time period of a second pendulum in that satelite.

The time period of a seconds pendulum is

The mass and radius of a satellite is twice that of the earth. If a seconds pendulum is taken to that satellite, what will be its time period?

The mass and diameter of a planet are twice those of the earth.What will be the period of oscillation of a pendulum on this planet,If it's a 2 second's pendulum on the earth?

What is the value of the time period of revolution of a geostationary satellite ?

The radius of the earth = R. if a geostationary satellite is revolving along a circular path at an altitude of 6R above the surface of the earth, what will be the time period of revolution of another satellite revolving around the earth at an altitude of 2.5R ?

An artificial satellite revolves around the earth in a circular orbit and is at a height of 300 km above the surface of the earth. Find the orbital speed and the time period of the satellite. The radius of the earth=6400 km, g=980 cm*s^(-2) .

The length of a seconds pendulum on the surface of the earth is