The maximum acceleration as time period of motion of a particle executing SHM is `5.0m//s^2` and 6.28s respectively. Find its
velocity when displacement is 4m

The time period and amplitude of a particle executing SHM are 10 s and 0.12 m respectively. Find its velocity at a distance 0.04 m from its position of equilibrium.

Write the equation of motion of a particle executing SHM if at t = 0 its displacement is maximum.

Time period and amplitude of a particle executing SHM are 2 s and 5 cm respectively. Determine its velocity and acceleration at a distacne of 3 cm from the equilibrium position.

The maximum acceleration of a particle executing simple harmonic motion is 0.296m*s^(-2) , its time period is 2s and the displacement from the equilibrium position at the beginning of its motion is 0.015m. Determine the equation of motion of the particle.

If the displacement and the acceleration of a particle executing SHM at any instant are x and a respectively, then the time period of that motion will be

The phase difference between displacement and velocity of a particle executing S.H.M. is given by.