A particle moves in x y plane. The position vector of the particle at any time t is `vecr = {(2t) hati+(2t^2)hatj}m`. The rate of change of at time t = 2 sec (where `theta` is the angle which its velocity vector makes with positive x axis) is :

Options

A. 2/(17) rad/(sec)
B. 1/(14) rad/(sec)
C. 4/7 rad/(sec)
D. 6/5 rad/(sec)

Answer

A