The position of a particle is given by,
`vecr = (3.0t hati -2.0t^2 hatj + 4.0 hatk)m`
where r is in seconds and the coefficients have the proper units for r to be in metres.
Find the `vecv` and `veca` of the particle.

The position of a particle is given by, vecr = (3.0t hati -2.0t^2 hatj + 4.0 hatk)m where t is in seconds and the coefficients have the proper units for r to be in metres. What is the magnitude and direction of velocity of the particle at t = 2.0 s ?

The position vector of a particle is, vecr=3thati-2t^2hatj+4hatk . Find out (i) its velocity vecv and acceleration veca ,

The position vector of a particle is, vecr=3thati-2t^2hatj+4hatk . Find out (ii) the magnitude and direction of its velocity at t=2s.

The position vector of a particle vecr =(t^2-1)hati +2thatj . Determine the trajectory of the particle in the xy plane.

The position coordinate of a moving particle is given by x = 6+18t +9 t^(2) (where x is in metre, t in seconds. What is its velocity and acceleration at t = 2 s.