A particle starts from the origin at t = 0 s with a velocity of `10.0hatj m/s` and moves in the X-Y plane with a constant acceleration of `(8.0 hati+2.0 hatj) m/s^2`.
At what time is the x-coordinate of the particle 16 m? What is the y-coordinate of the particle at that time ?

A particle starts from the origin with a velocity 5 cm/s and moves in a straight line its accelration at time t seconds being (3t^(2)-5t)cm//s^(2) . Find the velocity of the particle and its distance from the origin at the end of 4 seconds.

A particle moves for 1 minute with a velocity of 15 m/s and moves for 0.5 minute with a velocity of 10 m/s. the average speed of particle is

A particle starting from a point A and moving with a positive constant acceleration along a straight line reaches another point B is time T. Suppose that the initial velocity of the particle is u gt0 and P is the midpoint of the line AB. If the velocity of the particle at point P is v_(1) and if the velocity at time (T)/(2) is v_(2) , then -

A particle moves with a velocity 5hati -3hatj+6hatkm//s under the influence of a constant force, vecF =10 hati+20hatk N. The instantaneous power applied to the particle is

A particle starts from the origin and moves along a straight line. If the velocity of the particle at time t seconds be 10t cm/s, find the distance traversed during first 4 seconds after the start.