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A particle moves in the xy plane with ve...

A particle moves in the xy plane with velocity `vecv = phati+ qxhatj` where `hati` and `hatj` are unit vectors in the direction of x and y-axis, p and q are constants. At the initial moment of time, the particle was located atthe point x = y = 0. Find the equation of ihe trajectory of the particle.

A

`y = (px^2)/(2q)`

B

`y = x^2/(2pq)`

C

`y = (px^3)/(2q)`

D

`y = (qx^2)/(2p)`

Text Solution

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The correct Answer is:
D
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