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A Bomber flying upward at an angle of 53...

A Bomber flying upward at an angle of `53^@` with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 sec after its release. Find :
the velocity (magnitude and direction) of the bomb just when it strikes the ground.
(`sin 53^@ = 0.8, g =10m/s^2`]

Text Solution

Verified by Experts

`theta = tan^-1(7/4)` `V = `20sqrt(65) m/s`]
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