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A particle moves with deceleration along...

A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli . At the initial moment t=0 the speed of the particle equals `v_0`, then the speed of the particle as a function of the distance covered s will be

A

`v=v_0e(-s/R)`

B

`v=v_0e(s/R)`

C

`v=v_0e(-R/s)`

D

`v=v_0e(R/s)`

Text Solution

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The correct Answer is:
A
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