The focal length of a bi-convex glass `(mu_g = 1.5)` in air is 20 cm. Find its focal lengths in water `(mu_w = 1.35)` and in carbon di-suphide `(mu_(cs)` = 1.65).

Focal length of a double convex glass (u_g = 1.5) lens of radii of curvatures 20 cm each immersed in water, (mu_w = 1.35)

The focal length of a biconvex glass (mu_g = 1.5) lens in air (mu_alpha = 1) is + 20 cm . Then the focal length of this glass lens in water (mu_omega = 1.33) is

focal length double convex glass (u_g = 1.5) lens of radii of curvatures 20 cm each immersed in air is (u_a = 1)

A double convex glass (u_g = 1.5) lens of radii of curvatures 20 cm each immersed in carbno disulphide, (mucs_2 = 1.65) .Find the focal length.

The radii of curvatures of both surfaces of a double convex lens made of glass, (mu = 1.5) is R. Its focal length is

A convex lens made of glass (n_g = 1.5) is immersed in a liquid of refractive index n_1 = 1.65 . The lens then behaves as a

Fill in the blank spaces with appropriate answers: If a convex lens of glass (mu = 1.5) is put inside carbon disulphide (mu = 1.65) then the nature of the lens changes from ____to ____.