The radius of a planet is 1/4th of Re and its acc. due to gravity is 2g. What would be the value of escape velocity on the planet, if escape velocity on earth i`v_(e)`

If the radius of a planet is four times that of earth and the value of g is same for both, the escape velocity on the planet will be

If the radius of a planet is four times that of earth and the value of g is same for both, the escape velocity on the planet will be

The acceleration due to gravity on a planet is same as that on earth and its radius is four times that of earth. What will be the value of escape velocity on that planet if it is v_(e) on earth

Mass and radius of a planet are two times the value of earth. What is the value of escape velocity from the surface of this planet?

The radius of a planet is 1/4 of earth’s radius and its acceleration due to gravity is double that of earth’s acceleration due to gravity. How many times will the escape velocity at the planet’s surface be as compared to its value on earth’s surface

A planet has a mass 120 times that of earth and radius is 5 times the radius of earth. What is the escape velocity at this planet if the escape velocity at earth's surface is 11.2 km s^(-1) .

The radius of a planet is double that of the earth but then average densities are the same. If the escape velocities at the planet and at the earth are v_(P) and v_(E) respectively, then prove that v_(P)=2 v_(E).

A bullet is fired vertically upwards with a velocity upsilon from the surface of a spherical planet when it reaches its maximum height, its acceleration due to the planet's gravity is (1)/(4)th of its value at the surface of the planet. If the escape velocity from the planet is V_("escape") = upsilon sqrt(N) , then the value of N is : (ignore energy loss due to atmosphere).