The specific conductance of a 0.12 N solution of an electrolyte is `2.4xx10^(-2) S Cm^(-1) ` . Calculate its equivalent conductivity,

The specific conductance of a 0.01 M solution of KCl is "0.0014 ohm"^(-1)" cm"^(-1) at 25^(@)C . Its equivalent conductance is ...............

The specific conductance of a "0.20 mol.L"^(-1) solution of KCl at 300 K is "0.026S.cm"^(-1) . Calculate molar conductivity of the solution.

Specific conductance of "1 M KNO"_(3) solution is observed to be 5.55 xx 10^(-3)" mho.cm"^(-1) . What is the equivalent conductance of KNO_(3) when one litre of the solution is used ?

At a given temperature, specific conductance of 0.001(M) acetic acid solution is 5xx10^(-5)"S.cm"^(-1) and equivalent conductivity at infinite dilution is "390.5 S.cm"^(2).mol"^(-1) . What is the value of dissociation constant of acetic acid at the same temperature.

The conductivity of 0.001 mol solution of CH_(3)COOH is 3.905xx10^(-5)" S.cm"^(-1) . Calculate its molar conductivity and degree of dissociation (alpha) . ["Given: "lambda^(@)(H^(+))="349.6 S.cm"^(2)."mol"^(-1) and lambda^(@)(CH_(3)COO^(-))="40.9 S.cm"^(2)."mol"^(-1)]

At 25^(@)C resistance of 0.01 (N) KCl and 0.01 (N) HCl solutions in the same conductivity cell are 150 ohm and 51.40 ohm, respectively. The specific conductance of the KCl solution at 25^(@)C is 1.41xx10^(-3)" ohm"^(-1).cm"^(-1) . Determine the molar conductivity of HCl solution 25^(@)C .

The specific conductance of 0.01 (N) KCl solution at 25^(@)C, is "0.00140 ohm"^(-1)."cm"^(-1) . The same conductivity cell when filled with ((N)/(100))NaOH solution, the resistance of the solution was 14.8 ohm. If the resistance of the KCl solution is 25 ohm, what will be the equivalent conductivity of NaOH at 25^(@)C ?

At a certain temperature, the specific conductance of 0.001 (M) aqueous solution of acetic acid is 5xx10^(-5)"S.cm"^(-1) . At the same temperature, if the molar conductivity of an infinitely dilute aqueous solution of acetic acid is "400 S.cm"^(2)."mol"^(-1) , then -

The electrodes (5cmxx1cm) are held parallel at a distance of 1.5 cm apart and are dipped in a 0.1 (N) solution of an electrolyte. The resistance measured was 50 ohm. What will be the equivalent conductivity of the solution?

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S.cm^(-1) . Calculate the molar conductivity of the KCl solution.