Show that in a first order reaction, time required for completion of `99.9%` is 10 times of half-life `(t_1/2)` of the reaction

Show that for any first order reaction, the time required for the completion of 99.9% of the reaction is 10times the half-life of the reaction.

A first order reaction takes 60 minutes for 75% completion. Determine its half- life.

25% of a first order reaction is completed in 30 min . Find the time required for completion of 50% of the reaction.

For a first order reaction the ratio of times to complete 99.9% and half of the reaction is

For a first order reaction , show that time required for 99% completion is twice the time required for the completion of 90% of reaction.

The half life period of a first order chemical reaction is 6.93 minutes. The time required for the completion of 99% of the chemical reaction will be (log 2=0.301)

In a zero -order reaction , initial concentration of the reactant is a and value of the constant is k . If the time required for the completion of the reaction is t and the value of its half-life t_(1//2) then-

A first order reaction is found to have a rate constant, k= 5.5 xx 10^-14 s^-1 .Find the half-life of the reaction.

The initial concentration of the reactant in a first order reaction is a . It takes time t for the completion of noth fraction of the reaction. Will it take time 2t for the completion of the same fraction if the initial concentration of the reactant is made twice ?