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Half fife of a first order reaction is 6...

Half fife of a first order reaction is 60 min. How long will it take to consume `90%` of the reaction’?

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`t_(1/2) = 60 min therefore k = 11.55 xx 10^-3 min^-1`
`t = (2.303)/(11.55xx10^-3 log_(10)^(10) = (2.303)/(11.55xx10^-3 = 199 min`
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