A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour of 2.8 kPa at 298 K. Further, 18g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate,
molar mass of the solute

20 g of NaOH is present in 250 mL of H_(2) O . Calculate the active mass of the solution .

A solution is prepared by dissolving 10 g of nonvolatile solute in 180 g of H_2O . If the relative lowering of vapour pressure is 0.005, find the mol. wt. of the solute.

At 298 K, 100 cm of a solution containing 3.02 g of an unidentified solute exhibits an osmotic pressure of 2.55 atmosphere. What is the molecular mass of solute?

A solution containing 0.5 g of naphthalene in 50 g C Cl_4 yield a boiling point elevation of 0.4 k, while a solution of 0.6 g of an unknown solute in the same mass of the solvent gives a boiling point elevation of 0.65 k. Find the molar mass of the unknown solute.

For a dilute solution containing 2.5 g of a non- volatile non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm pressure is 2^@C Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of Hg) of the solution is (take k_b = 0.76 K kg mol^(-1)) .

Two liquids A and B form an ideal solution. At 300 k, the vapour pressure of a solution containing 1 mole of A and 3 moles of B is 550 mm of Hg. At the same temperature, if one mole of B is added to this solution, the vapour pressure of the solution increases by 10 mm of Hg. Determine the vapour pressure of A and B in their pure states.

The solubility of a specific non-volatile salt is 4 g in 100 g of water at 25^@C . If 2.0 g, 4.0 g and 6.0 g of the salt added to 100 g of water at 25^@C , in system X, Y and Z. The vapour pressure would be in the order :

A solution containing 2.5 g of a non-volatile solute in 100 gm of benzene boiled at a temperature 0.42K higher than at the pure solvent boiled. What is the molecular weight of the solute? The molal elevation constant of benzene is "2.67 K kg mol"^(-1) .

214.2 g of sugar syrup contains 34.2 g of sugar. Calculate :- Molality of the solution.