A solution containing 0.5 g of naphthalene in 50 g `C Cl_4` yield a boiling point elevation of 0.4 k, while a solution of 0.6 g of an unknown solute in the same mass of the solvent gives a boiling point elevation of 0.65 k. Find the molar mass of the unknown solute.

A solution contains 5.6 gm of glucose in 1000 gm of water. Calculate the boiling point of the solution. ( k_b for water = 0.52 K kg mol^-1 )

A solution is prepared by dissolving 10 g of nonvolatile solute in 180 g of H_2O . If the relative lowering of vapour pressure is 0.005, find the mol. wt. of the solute.

Derive the relation between molar mass of solute and elevation of boiling point

Derive the relation between molar mass of solute and elevation of boiling point

A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour of 2.8 kPa at 298 K. Further, 18g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate, molar mass of the solute

At 298 K, 100 cm of a solution containing 3.02 g of an unidentified solute exhibits an osmotic pressure of 2.55 atmosphere. What is the molecular mass of solute?

At 100^@C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If K_b = 0. 52, the boiling point of this solution will be.

For a dilute solution containing 2.5 g of a non-volatile non-electrolyte solute in 100 g water, the elevation of boiling point at 1 atm pressure is 2°C. Assuming concentration of solute is much lower than the concentration of solvent, determine the vapour pressure (mm Hg) of the solution. [Given: k_b for water = 0.76K-kg- mol^(- 1) ]

For a dilute solution containing 2.5 g of a non- volatile non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm pressure is 2^@C Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of Hg) of the solution is (take k_b = 0.76 K kg mol^(-1)) .