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0.436 g of acetyl derivative of a polyhy...

0.436 g of acetyl derivative of a polyhydric alcohol(molecular mass=92) requires 0.336 g of KOH for hydrolysis. Calculate the number of hydroxyl groups in the alcohol.

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Verified by Experts

We know,`w/W (M+42n)56n
Given:w=0.336g.W=0.436g, M=92
`implies(0.336)/(0.436) (92+42n)=56n`
`impliesn =3 implies `The alcohol is trihydric
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