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0.092 g of a compound with the molecular...

0.092 g of a compound with the molecular formula `C_3H_8O_3` on reaction with an excess of `CH_3MgI` gives 67.00 mL Of methane at STP. The number of active hydrogen atoms present in a molecule of the compound

A

one

B

two

C

three

D

four

Text Solution

Verified by Experts

The correct Answer is:
C
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