If an oil drop of weight 3.2xx10^(-13)N ...

If an oil drop of weight `3.2xx10^(-13)`N is balanced in an electric field of intensity `5xx10^(5)` V/m, find the charge on oil drop.

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`q=F/E=(3.2xx10^(-13))/(5xx10^5)=6.4xx10^(-19)C`

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