A slab of dielectric constant k has the same area as the plates of a parallel plate capacitor but has a thickness 3d/4, where is the separation between the plates. How is the capacitance changed, when the slab is inserted between the plates

A slab of material of dielectric constant k has the same area as the plates of parallel plate capacitor, but has a thickness (3)/(4)d , where d is the separation of the plates. How is the capacitance changed when the slab is inserted between the plates?

A slab of material of dielectric constant k has the same area as that of the plates of a parallel plate capacitor but has the thickness d/2, when d is the separation between the plates. Find out the expression for its capacitance when the slab is inserted between the plates of the capacitor.

What is an equipotential between the plates of a parallel plate capacitor.

What will be the change in the capacitance of a parallel plate air capacitor if A conducting slab fills the space between the plates of the capacitor?

A parallel plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected. A slab of dielectric constant k is then inserted between the plates of the capacitor so as to fill the space between the plates. If Q, E and W denote respectively the charge on each plate, the electric field between the plates and the work done in the process of inserting the slab, then

The distance between the plates of a parallel plate capacitor is d. A metal plate of thickness (d)/(2) is placed between the plates. What will be its effect on the capacitance of the system?