An infinite line charge produces a field of `9times10^4N//C` at a distance of 2 cm. Calculate the linear charge density.

An infinite line charge produces a field of 9 xx 10^(4) N. C^(-1) at a distance of 2 cm. Calculate the linear charge density.

An electric dipole is formed by placing charges pm 20 xx 10 ^( -6 ) C at a distance 2 mm. Calculate the electric field at a point on the perpendicular bisector of the axis of the dipole situated at a distance 10 cm from the midpoint of the dipole.

Find out the energy content in a volume of 1 cm^3 around a point, situated in the electric field of a point charge of 10C, at a distance of 2 m in air from the position of the point charge. Given, in_0 = 8.85 xx10^(-12)F*m^(-1) .

Find the electric field and potential at the centre of curvature of a uniformly charged semicircular rod of radius R with a total charge Q in SI. lambda is the linear charge density.

The electric potential at a certain distance from a point charge is 600V and the electric field is 200 N//C . The distance of the point charge (in metres) is:

Statement I : Due to an infinitely long linear charge distribution, potential at any point at a distance r from the line is proportional to log r. Statement II : E prop 1/r and E = -(dV)/(dr) .

An electric dipole is formed by two equal but opposite charges , each of magnitude 1mu C , separated by a distance of 5 cm. what is the magnitude of the torque required to place the dipole at right angles to an electric field of intensity 3 xx 10^5 N * C ^ ( - 1 ) ?

An electric field of intensity 9 xx 10^(4)N//C is produced at a point 2 cm away from an infinitely long straight charged conducting wire . Electric charge per unit length becomes

Use Gauss' law to derive the expression for the electric field (vecE) due to a straight uniformly charged infinite line of charge density lambda C cdot m^(-1) .