Two large thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude `17.0times10^(-22)C//m^2`. What is E :
in the outer region of the first plate

Two large thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 17.0times10^(-22)C//m^2 . What is E : in the outer region of the second plate

Two large thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 17.0times10^(-22)C//m^2 . What is E : between the plates ?

Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 17.0 xx 10^(-22) C .m^(-2) .What is the electric field In the outer region of the first plate ?

Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 17.0 xx 10^(-22) C .m^(-2) .What is the electric field In the outer region of the second plate ?

Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 17.0 xx 10^(-22) C .m^(-2) .What is the electric field between the plate ?

A parallel plate capacitor has plates A and B each of area 0.5m^2 and a plate separation of 0.2 m. A dielectric slab of thickness 0.1m and dielectric constant 2.5 is placed between the two plates as shown - (a) FInd the capacitance of the capacitor, if the surface charge densities of the two plates are 8.854xx10^(-10)Cm^(-2) . (b) Graphically represent the variation of electric field between the two plates from A to B.

Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (1/2)QE, where Q is the charge on the capacitor, and E is the magnitude of electric field between the plates. Explain the origin of the factor 1/2