The number density of free electrons in a copper conductor is `8.5xx10^28m^(-3)`. How long does an electron take to drift from one end of a wire 3.0 m long to its other end? The area of cross-section of the wire is `2.0xx10^(-6)m^2` and it is carrying a current of 3.0A.

The number density of conduction electron in copper is 8.5xx10^28(m^-3) and the mean free time between two collision is 2.5xx10^-14 s. What is the conductivity of copper ?

The number of free electrons per unit volume in a metallic conductor is 10^22 cm^-3 .The area of cross section of the conductor is 1mm^2 and the strength of current through the conductor is 1A. Determine the drift velocity of the free electrons,(Given that the charge of an electron -1.6 times 10^-19 C )

Resistance of a 10m long and 10^(-6) m^2 cross-section wire made of material having resistivity 10^(-6)Omega m is :

A closely wound solenoid of 800 turns and area of cross section 2.5xx10^(-4)m^2 carries a current of 3A. What is its associated magnetic moment?

Calculate the change in length of a wire of length 5 m undergoing a strain of 1% of 0.1. IF the area of cross section of the wire is 1mm^2 and the load applied on it is 10 kg then find the ratio of stress to strain.

A 0.5 m long solenoid has 500 turns and has a flux density of 2.52xx10^(-3)T at its centre. Find the current in the solenoid.

When a tensile force of 60 N is applied to a metal wire of length 50 m and ara of cross- section 10^(-6)m^(2) , elengation of the wire is 4xx10^(-3) m. calculate (i) stress and (ii) strain.

When a load of 10 kg is hung from one end of a wire of length 5 m, the wire elongates by 5 mm. IF the young modulus for the material of the wire is 9.8 times 10^10 N.m^-2 , then find the area of cross section of the wire. [g=9.8 m.s^-2 ]

If the current in the primary circuit of a potentiometer wire is 0.2A, specific resistance of the material of wire 40xx10^(-8)Omega m and area of cross-section of wire is 8xx10^(-7)m^2 . The potential gradient will be

The area of cross section of a steel wire (Y=2.0xx10^11 N//m^2) is 0.1 cm^2 . The force required to double its length will be