A storage battery of emf 8.0V and internal resistance `0.5Omega` is being charged by a 120V de supply using a series resistor of `15.5Omega`. What is the terminal voltage of the battery during charging? What is the purpose of having a series resistor in the charging circuit?

A storage battery of emf 8.0 V and internal resistance 0.5 Omega is being charged by a 120 V dc supply using a series resistor of 15.5 Omega .What is the terminal voltage of the battery during charging? What is the purpose of using the series resistor in the charging circuit?

A battery of emf 10V and internal resistance 3 ohm is connected to a resistor. If the current in the circuit is 0.5A, what is the resistance of resistance of resistor ? What is the terminal voltage of the battery when the circuit is closed?

Two cells , one of emf 1.2 V and internal resistance 0.5Omega the other of emf 2 V and internal resiatnce 0.1Omega are connnected in series with an external resistance of 5Omega . What is the current through this resistor ?

Six lead acid type of secondary cells, each of emf 2.0V and internal resistance 0.015Omega , are joined in series to provide a supply to resistance of 8.5Omega What are the current drawn from the supply and its terminal voltage?

A cell of emf E and internal resistance r is connected across a variable resistor R. Plot a graph showing variation terminal voltage V of the of the cell Versus the current I. Using the plot,show how the emf of the cell and its internal resistance can be determined.

A 100V battery has an internal resistance 3 Omega . What is the reading of a voltmeter having resistance 200 Omega , when placed across the terminals of the battery? What should be the minimum value of the voltmeter resistance so that the error in finding the emf of the battery may not be more than 1%?

An electric cell of emf 10 V and of internal resistance 1 Omega is connected in series with the parallel combination of three resistances of 3 Omega,5 Omega and 8 Omega .Calculate the currents through the three resistances.

A cell of emf 1.4V and internal resistance 2 Omega is connected in series with a resistance of 100 Omega and an ammeter. The resistance of the ammeter is 4/3 Omega .To measure the potential difference between the two ends of the resistance a voltmeter is connected .Draw the circuit

A cell of emf 1.5 V and of internal resistance 0.1Omega when connected with a resitor and an ammeter of negligible resistance in series , the ammeter shows a 2.0 A steady current . Find (ii) the power consumed in the resistor .

A battery of emf 1.4V and interna! resistance 2Omega is connected to a resistor of 100Omega resistance through an ammeter. The resistance of ammeter is 4/3Omega a voltmeter has also been connected to find the potential difference across the resistor. The ammeter reads 0.02 A. What is the resistance of voltmeter.