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The resistance of a potentiometer wire o...

The resistance of a potentiometer wire of length 10m is 20 ohm. A resistance box and a 2 volt accumulator are connected series with it. Resistance required to be introduced in the box to have a potential drop of one microvolt per millimeter of the potentiometer wire will be

A

`3880Omega`

B

`3980Omega`

C

`2500Omega`

D

`3600Omega`

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A potentiometer wire has a length 10m and a resistance of 4 ohm. A cell of emf 2V and a resistance box are connected in series with it. Calculate the resistance to be introduced in the box, so as to get a potential gradient of 0.1Vm^-1 .

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Knowledge Check

  • A potentiometer wire has length 4m and resistance 8Omega the resistance that must be connected in series with the wire and an accumulaterof emf 2 V so as to get a potential gradient 1 mV ,per cm on the wire is

    A
    `32Omega`
    B
    `40Omega`
    C
    `44Omega`
    D
    `48Omega`

  • A potentiometer wire of length L and a resistance r are connected in series with a battery of e.m.f. E_0 and a resistance r_1 An unknown e.m.f. E is balanced at a length I of the potentiometer wire. The e.m.f. E will be given by

    A
    `(E_0r1)/(r'r_1L)2`
    B
    `(E_0I)/L`
    C
    `(LE_0r)/((r'r_1)I)`
    D
    `(LE_0r)/(Ir_1)`

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