A magnetic needle suspended in a vertical plane at `30^@` from the magnetic meridain makes an angle of `45^@` with the horizontal find the true angle of dip.

A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip down at 60^@ with the horizontal. The horizontal component of the earth's magnetic field at the place is known to be 0.4G. Determine the magnitude of the earth's magnetic field at the place.

A circular coil of 30 turns and radius 8.0 cm carrying a current of 6.0A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0 .The field lines make an angle of 60^(@) with the normal of the coil. Calculate the magnitude of the counter torque that must be applied to prevent the coil turning.

A circular coil of 30 turns and radius 8.0 cm carrying current of 6.0 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0 T. The field lines make an angle of 60^@ with the normal to the coil. Calculate the magnitude of the counter torque, that must be applied to prevent the coil from turning.

The vertical component of earth's magnetic field at a place is sqrt(3) Times of the horizontal component. What is the angle of dip at this place ?

A square coils of side 10 cm consists of 20 turns and carries a current of 12A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of 30^(@) with the direction of a uniform horizontal magnetic field of magnitude 0.80T . What is the magnitude to torque experienced by the coil ?

Shib is flying kite having the length of thread 250 metres, when the thread makes an angle 60^(@) with the horizontal line and when the thread makes an angle of 45^(@) with the horizontal line. Calculate in each case what is the height of kite from the ground. Also find in which of the two cases will the kite be at a greater height from the other.