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for a circular coil of radius R and N tu...

for a circular coil of radius R and N turns carrying a current I the magnitude of magnetic field at a point on its axis at a distance x from its centre is given by `B= (mu_0IR^2N)/(2(x^2+R^2)^(3/2)`
show that this reduces to the standard result for field at the centre of the coil.

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For a circular coil of radius R and number of turns N carrying a current I, the magnitude of the magnetic field at a point on its axis at a distance x from its centre is given by B=(mu_(0)IR^(2)N)/(2(x^(2)+R^(2))^(3//2) Consider two parallel co-axis circular coils of equal radius R and number of turns N, carrying equal current in the same direction and separated by a distance R. Show that the field on the axis around the mid-point between the coils is uniform over a distance that is small compared to R and is given by B=0.72 mu_(0) NI//R , approximately. (Such an arrangement to produce a nearly uniform magnetic field over a small region is know as Helmholtz coils).

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