A uniform magnetic field of 30 m T exists in the X direction.A particle of charge `+1.6xx10^(-19) C` and mass `1.67xx10^(-27)` kg is projected through the field in the +y direction with a speed of `4.8xx16^6 m/s.
Describe the nature of path followed by the particle in both the cases.

Explanation

As `vbodB` the path decribed is a circle where radius is given by `R=(mv)/(qb)=1.67xx10^(-27) (4.8xx10^6)//(1.6xx10^(-19)(30xx10^(-3))`=1.67m