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Show that : tanx -x is strictly increas...

Show that : tanx -x is strictly increasing on `(0,pi/2)`.

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Let f(x)= tanx -x therefore f.(x)=sec^2x-1`
`x in (0,pi/2)impliessec^2x-1>0implies f.(x)>0`
therefore f(x) is strictly. increasing on `(0,pi/2`.
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