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The equation of the normal to the curve ...

The equation of the normal to the curve `y=e^(-2|x|` at the point where the curve cuts the line `x=-1/2`, is

A

`2e(ex+2y)=4-e^2`

B

`2e(ex-2y)=e^2-4`

C

`2e(ey-2x)=e^2-4`

D

`2e(ey+2x)=e^2-4`

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The correct Answer is:
A
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PATHFINDER-APPLICATION OF DERIVATIVE-QUESTION BANK
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