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If |f(x2)-f(x1)|le(x2-x1)^2AAx1,x2inR, t...

If `|f(x_2)-f(x_1)|le(x_2-x_1)^2AAx_1,x_2inR,` then the equation of tangent to the curve y = f(x) at the point (1,2) is

A

y=2

B

`y=-2`

C

`y=2x+1`

D

none of these

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The correct Answer is:
D
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