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For every real number x, f(x)=x/(1!)+3...

For every real number x,
`f(x)=x/(1!)+3/(2!)x^2+7/(3!)x^3+15/(4!)x^4+…` < br> Then the equation f(x)=0 has

A

no real solution

B

exactly one real solution

C

exactly two real solution

D

infinite number of real solutions

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The correct Answer is:
B
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PATHFINDER-APPLICATION OF DERIVATIVE-QUESTION BANK
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