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Find int cos 6x sqrt(1 + sin 6x)dx...

Find `int cos 6x sqrt(1 + sin 6x)dx`

Text Solution

Verified by Experts

Put = 1 + sin 6x , so that dt = 6 cos 6x dx
Therefore `int cos 6x sqrt(1 + sin 6x) dx = 1/6 int t^(1/2) dt`
= `1/6 xx 2/3 (t)^(3/2) + C = 1/9 (1 + sin 6x)^(3/2) + C`
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