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If I = int (sin x + sin^3 x)/(cos 2x) dx...

If `I = int (sin x + sin^3 x)/(cos 2x) dx = A cos x + B log abs(f(x)) + c`, then find A, B, f(x).

A

A = 1/4 , B = -1/2 , `f(x) = (sqrt2 cos x - 1)/(sqrt2 cos x + 1)`

B

A = 1/2 , `B = -3/4sqrt2`

C

A = -1/2 , `B = 3/sqrt2 , f(x) = (sqrt2 cos x +1)/(sqrt2 cos x - 1)`

D

A = 1/2 , `B = -3/sqrt2 , f(x) = (sqrt2 cos x +1)/(sqrt2 cos x - 1)`

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The correct Answer is:
B, D
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PATHFINDER-INDEFINITE INTEGRATION-QUESTION BANK
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