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I=intsin^-1((2x)/(1+x^2)) dx is equal to...

`I=intsin^-1((2x)/(1+x^2)) dx` is equal to

A

`2xtan^-1(x)-logabs(x^2+1)+c`

B

`2x[tan^-1(x)-logabs(x^2+1)]+c`

C

`2xtan^-1(x)+logabs(x^2+1)+c`

D

`tan^-1x-logabs(x+1)+c`

Text Solution

Verified by Experts

The correct Answer is:
A
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