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int(cos2x)/(cosx)dx=...

`int(cos2x)/(cosx)dx`=

A

`2sinx+logabs(secx+tanx)+c`

B

`2sinx-logabs(secx-tanx)+c`

C

`2sinx-logabs(secx+tanx)+c`

D

`2sinx+logabs(secx-tanx)+c`

Text Solution

Verified by Experts

The correct Answer is:
C
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