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I= int(-pi)^(pi) (e^sinxdx)/(e^sinx +e^(...

`I= int_(-pi)^(pi) (e^sinxdx)/(e^sinx +e^(-sinx)` then `I` equals

A

`(pi)/2`

B

`2pi`

C

`pi`

D

`(pi)/4`

Text Solution

Verified by Experts

The correct Answer is:
C
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