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The correct Answer is:
S CHAND-QUESTION BANK-7. अवकलन
- int(0)^(1)((tan^(-1)x)^(2))/(1+x^(2))dx=
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- int(-2)^(2)|x|dx=
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- int(-pi//2)^(pi//2)sin^(9)x dx=
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- int(0)^(pi//2)(dx)/(1+tan^(3)x)=
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- int(0)^(pi//2)cos x e^(sinx)dx=
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- int(0)^(pi^(2)//4)(sinsqrt(y))/(sqrt(y))dy=
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- int(0)^(8)1/(1+e^(x))dx=
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- int(0)^(1)sqrt(x(1-x))dx
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- int(1)^(3)(cos(logx))/xdx=
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- int(-pi//2)^(pi//2)(x^(3)+xcosx+tan^(5)x+1)dx=
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- int(0)^(1)tan((2x-1)/(1+x-x^(2)))dx=
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- int(0)^(pi//2)log((4+3sinx)/(4+3cosx))dx=
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- int(0)^(1)xe^(x)dx=
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- int(0)^(1)sin^(-1)x dx=
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- int(0)^(pi//4)2 tan^(3)x dx=
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- int(0)^(pi//2)(sqrt(tanx))/(sqrt(tanx)+sqrt(cotx))dx=
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- int(0)^(pi//2)(sinx-cosx)/(1+sinx cosx)dx=
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- int(0)^(a)f(x)dx=
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- int(a)^(c)f(x)dx+int(c)^(b)f(x)dx=
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- int(-1)^(1)sin^(3)xcos^(3)x dx=
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